{"id":35851,"date":"2024-03-05T05:29:00","date_gmt":"2024-03-05T03:29:00","guid":{"rendered":"https:\/\/www.nsa.smsm.lt\/old\/?page_id=35851"},"modified":"2024-09-04T09:56:34","modified_gmt":"2024-09-04T07:56:34","slug":"fizika","status":"publish","type":"page","link":"https:\/\/www.nsa.smsm.lt\/old\/egzaminai-ir-pasiekimu-patikrinimai\/2024-2025-m-pasiekimu-patikrinimai\/fizika\/","title":{"rendered":"Fizika"},"content":{"rendered":"<h2>2024 &#8211; 2025 m. m.<\/h2>\n<p><a href=\"https:\/\/beta.etestavimas.lt\/tests\/view\/973f4ad12406\/545\">Fizikos valstybinio brandos egzamino pirma dalis. U\u017eduoties pavyzdys<\/a><\/p>\n<p><a href=\"https:\/\/www.nsa.smsm.lt\/old\/old\/wp-content\/uploads\/2024\/09\/1-dalies-VBE-vertinimo-instrukcija_fizika.pdf\">Fizikos valstybinio brandos egzamino pirmos dalies kandidat\u0173 darb\u0173 vertinimo instrukcija<\/a><\/p>\n<p><a href=\"https:\/\/www.nsa.smsm.lt\/old\/old\/wp-content\/uploads\/2024\/09\/FIZIKA_2-dalies-VBE-uzduotis_FIN_R1.pdf\">Fizikos valstybinio brandos egzamino antros dalies u\u017eduotis<\/a><\/p>\n<p><a href=\"https:\/\/www.nsa.smsm.lt\/old\/old\/wp-content\/uploads\/2024\/09\/FIZIKA_2-dalies-VBE-vertinimo-instrukcija_FIN.pdf\">Fizikos valstybinio brandos egzamino antros dalies kandidat\u0173 darb\u0173 vertinimo instrukcija<\/a><\/p>\n<h2>2023 &#8211; 2024 m. m.<\/h2>\n<p><a role=\"link\" href=\"https:\/\/beta.etestavimas.lt\/tests\/view\/3cd18a0db91c\/450\">Fizikos tarpinio patikrinimo u\u017eduoties pavyzdys<\/a><\/p>\n<p><a href=\"https:\/\/www.nsa.smsm.lt\/old\/old\/wp-content\/uploads\/2023\/09\/Fizikos-TP-uzduoties-vertinimo-instrukcija_2023-09-21.pdf\">Fizikos tarpinio patikrinimo u\u017eduoties pavyzd\u017eio vertinimo instrukcija<\/a><\/p>\n<p><a href=\"https:\/\/www.nsa.smsm.lt\/old\/old\/wp-content\/uploads\/2024\/03\/3-priedas.-Fizikos-formules-ir-konstantos.docx.pdf\">Fizikos valstybinio brandos egzamino formul\u0117s ir pagrindin\u0117s konstantos<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>2024 &#8211; 2025 m. m. Fizikos valstybinio brandos egzamino pirma dalis. U\u017eduoties pavyzdys Fizikos valstybinio brandos egzamino pirmos dalies kandidat\u0173 darb\u0173 vertinimo instrukcija Fizikos valstybinio brandos egzamino antros dalies u\u017eduotis Fizikos valstybinio brandos egzamino antros dalies kandidat\u0173 darb\u0173 vertinimo instrukcija&nbsp;<a href=\"https:\/\/www.nsa.smsm.lt\/old\/egzaminai-ir-pasiekimu-patikrinimai\/2024-2025-m-pasiekimu-patikrinimai\/fizika\/\" class=\"placiau\">Pla\u010diau <i class=\"fa fa-caret-right\"><\/i><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"parent":34932,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"page-2024pasiekimas.php","meta":{"_acf_changed":false,"footnotes":""},"class_list":["post-35851","page","type-page","status-publish","hentry"],"acf":[],"_links":{"self":[{"href":"https:\/\/www.nsa.smsm.lt\/old\/wp-json\/wp\/v2\/pages\/35851","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.nsa.smsm.lt\/old\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/www.nsa.smsm.lt\/old\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/www.nsa.smsm.lt\/old\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.nsa.smsm.lt\/old\/wp-json\/wp\/v2\/comments?post=35851"}],"version-history":[{"count":15,"href":"https:\/\/www.nsa.smsm.lt\/old\/wp-json\/wp\/v2\/pages\/35851\/revisions"}],"predecessor-version":[{"id":40701,"href":"https:\/\/www.nsa.smsm.lt\/old\/wp-json\/wp\/v2\/pages\/35851\/revisions\/40701"}],"up":[{"embeddable":true,"href":"https:\/\/www.nsa.smsm.lt\/old\/wp-json\/wp\/v2\/pages\/34932"}],"wp:attachment":[{"href":"https:\/\/www.nsa.smsm.lt\/old\/wp-json\/wp\/v2\/media?parent=35851"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}